What is the symmetry y=(x+9)(x-21) ?

The symmetry y=(x+9)(x-21) is y=6

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Find the Axis of Symmetry f(x)=(x+9)(x-21)

symmetry

y = (x + 9) (x - 21)

y = 6

Solution steps

y = (x + 9) (x - 21)

Rewrite in standard form:

y = x^{2} - 12 x - 189

y = x^{2} - 12 x - 189

Axis of Symmetry for

y = a x^{2} + b x + c

x = \frac{- b}{2 a}

a = 1, b = - 12

y = \frac{- ( - 12 )}{2 \cdot 1}

Refine

y = 6

10 x - 5 y = - 30

- 6 x - 2 y = 10

y = sin (x)

g (x) = (x - 7.5)^{2}

f (x) = x, - 4 \leq x \leq 4