What is the f(x)(g(x))f(x)=x-2,g(x)= 1/x ?

The f(x)(g(x))f(x)=x-2,g(x)= 1/x is (\circ f(x)^2)/(x^2)

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Find f(g(x)) f(x)=x-2 , g(x)=1/x

f (x) (g (x)) f (x) = x - 2, g (x) = \frac{1}{x}

\frac{\circ f ( x ) ^{2}}{x ^{2}}

Solution steps

Find

f (x) (g (x)) f (x) \circ g

given

f (x) (g (x)) f (x) (x) = x - 2, g (x) = \frac{1}{x}

f (x) (g (x)) f (x) \circ g = f (x) (g (x)) f (x) \circ g (x)

g (x) = \frac{1}{x}

g (x) = \frac{1}{x}

= f (x) \frac{1}{x} f (x) \circ \frac{1}{x}

Expand

f (x) \frac{1}{x} f (x) \circ \frac{1}{x} : \frac{\circ f ( x ) ^{2}}{x ^{2}}

= \frac{\circ f ( x ) ^{2}}{x ^{2}}

y - 4 = 2 (x - 3)

f (x) = 12 x - 10

y = 6 x^{2} + 36 x + 54

4 x - 3 y = 18

f (x) = x^{2} - x + 5

What is the f(x)(g(x))f(x)=x-2,g(x)= 1/x ?
The f(x)(g(x))f(x)=x-2,g(x)= 1/x is (\circ f(x)^2)/(x^2)