What is the f(x)=-3(x+1)^2-3 ?

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Write in Standard Form f(x)=-3(x+1)^2-3

f (x) = - 3 (x + 1)^{2} - 3

Domain : - \infty < x < \infty

Range : f (x) \leq - 3

Y Intercepts : (0, - 6)

Vertex : Maximum (- 1, - 3)

Inverse : - \frac{x + 3}{3} - 1, - - \frac{x + 3}{3} - 1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, - 3]

Solution steps

Domain of

- 3 (x + 1)^{2} - 3 : - \infty < x < \infty

Range of

- 3 (x + 1)^{2} - 3 : f (x) \leq - 3

Axis interception points of

- 3 (x + 1)^{2} - 3 :

Y Intercepts

: (0, - 6)

Vertex of

- 3 (x + 1)^{2} - 3 :

Maximum

(- 1, - 3)

Inverse of

- 3 (x + 1)^{2} - 3 : - \frac{x + 3}{3} - 1, - - \frac{x + 3}{3} - 1

f (x) = \frac{1}{2 x + 10}

x - 8 y = 40

7 x - 5 = 4 y - 6

x - 5 y = 5

f (x) = \frac{( 5 x - 7 )}{x}