What is the extreme f(x)=3x^2-30x-8 ?

The extreme f(x)=3x^2-30x-8 is Minimum(5,-83)

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Find the Maximum/Minimum Value f(x)=3x^2-30x-8

extreme points

f (x) = 3 x^{2} - 30 x - 8

Minimum (5, - 83)

Solution steps

f^{'} (x) = 6 x - 30

Find intervals:

Decreasing

: - \infty < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 5

into

3 x^{2} - 30 x - 8 : - 83

Minimum (5, - 83)

f (x) = 3 x - 6, (0, 4)

(4, 6), (- 1, - 14)

x = 1 f (x) = - 2 x^{2} - 3 x, x = 1

(- 4, - 2), (4, 12)

f (c) = - 13 c

What is the extreme f(x)=3x^2-30x-8 ?
The extreme f(x)=3x^2-30x-8 is Minimum(5,-83)