What is the extreme f(x)=3x^2-30x-8 ?

The extreme f(x)=3x^2-30x-8 is Minimum(5,-83)

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Find the Maximum/Minimum Value f(x)=3x^2-30x-8

extreme points

f (x) = 3 x^{2} - 30 x - 8

Minimum (5, - 83)

Solution steps

f^{'} (x) = 6 x - 30

Find intervals:

Decreasing

: - \infty < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 5

into

3 x^{2} - 30 x - 8 : - 83

Minimum (5, - 83)

y = 7 x - 3

f (x) = 0

6 x + 4 y = 8

f (x) (g (x)) f (x) = 4 x - 8, g (x) = 6 x - 4

4 x - 3 y = 24

What is the extreme f(x)=3x^2-30x-8 ?
The extreme f(x)=3x^2-30x-8 is Minimum(5,-83)