What is the y+1=(-1)/(2x),(-8,7) ?

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Find the Perpendicular Line Find the equation of a line perpendicular to y+1=-1/2x that passes through the point (-8,7)

y + 1 = \frac{- 1}{2 x}, (- 8, 7)

Domain : - 8 < x < 0 or 0 < x < 7

Range : f (x) < - \frac{1}{14} or f (x) > \frac{1}{16}

Intercepts : None

Asymptotes : Vertical x = 0, Horizontal None

Extreme Points : None

Interval Notation

Domain : (- 8, 0) \cup (0, 7)

Range : (- \infty, - \frac{1}{14}) \cup (\frac{1}{16}, \infty)

Solution steps

Domain of

\frac{- 1}{2 x}, (- 8, 7) : - 8 < x < 0 or 0 < x < 7

Range of

\frac{- 1}{2 x}, (- 8, 7) : f (x) < - \frac{1}{14} or f (x) > \frac{1}{16}

Axis interception points of

\frac{- 1}{2 x}, (- 8, 7) :

None

Asymptotes of

\frac{- 1}{2 x}, (- 8, 7) :

Vertical

: x = 0,

Horizontal

:

None

Extreme Points of

\frac{- 1}{2 x}, (- 8, 7) :

None

y = lo g_{10} (x)

f (x) = lo g_{10} (x) - 4

lo g_{3} (\frac{a}{3})

m = \frac{1}{3}, (- 3, 7)

g (x) = - x^{2} + 4 x + 9, - 2 \leq x \leq 4