What is the domain of y=sqrt(x^2+3) ?

The domain of y=sqrt(x^2+3) is -infinity <x<infinity

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domain of y=sqrt(x^2+3)

domain

y = x^{2} + 3

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

- 5 cos (6 x)

(0, 0), (4.6729, 16.617)

f (x) = 2 x^{3} - 12 x^{2} - 30 x + 9

- 12 x^{2} - 18 x

f (x) = x^{3} + x^{2}

What is the domain of y=sqrt(x^2+3) ?
The domain of y=sqrt(x^2+3) is -infinity <x<infinity