What is the domain of f(x)=-9/(2x^{3/2)} ?

The domain of f(x)=-9/(2x^{3/2)} is x>0

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domain of f(x)=-9/(2x^{3/2)}

domain

f (x) = - \frac{9}{2 x ^{\frac{3}{2}}}

x > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

(- 1.4) (5.2)

12 x^{4} + 4 y^{4} = 34

3 - ∣ x + 2 ∣

f (x) = x^{2} - \frac{3}{4}

y = x - 3

What is the domain of f(x)=-9/(2x^{3/2)} ?
The domain of f(x)=-9/(2x^{3/2)} is x>0