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Popular >

extreme f(x)=x^2+12x+40

Solution

extreme points

f (x) = x^{2} + 12 x + 40

Solution

Minimum (- 6, 4)

Solution steps

f^{'} (x) = 2 x + 12

Find intervals:

Decreasing

: - \infty < x < - 6,

Increasing

: - 6 < x < \infty

Plug

x = - 6

into

x^{2} + 12 x + 40 : 4

Minimum (- 6, 4)

Popular Examples

domain of f(x)=(log_{2}(x))+8 domain

f (x) = (lo g_{2} (x)) + 8

domain of f(x)=2*3^x domain

f (x) = 2 \cdot 3^{x}

simplify (-4.8)(-2.1)simplify

(- 4.8) (- 2.1)

asymptotes of f(x)=(4x^2+x-9)/(x^2+x-56)asymptotes

f (x) = \frac{4 x ^{2} + x - 9}{x ^{2} + x - 56}

intercepts of f(x)=2x-6 intercepts

f (x) = 2 x - 6

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+12x+40 ?
The extreme f(x)=x^2+12x+40 is Minimum(-6,4)