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Popular >

range of x^2-8x+7

Solution

range

x^{2} - 8 x + 7

Solution

f (x) \geq - 9

+1

Interval Notation

[- 9, \infty)

Solution steps

Vertex of

x^{2} - 8 x + 7 :

Minimum

(4, - 9)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (4, - 9)

f (x) \geq - 9

Popular Examples

extreme f(x)=xsqrt(64-x^2)extreme points

f (x) = x 64 - x^{2}

intercepts of f(x)=((x^2-1))/((2x))intercepts

f (x) = \frac{( x ^{2} - 1 )}{( 2 x )}

parity f(x)=sqrt(7)x parity

f (x) = 7 x

range of y=sqrt(x-8)range

y = x - 8

domain of 6/x domain

\frac{6}{x}

Frequently Asked Questions (FAQ)

What is the range of x^2-8x+7 ?
The range of x^2-8x+7 is f(x)>=-9