What is the inverse of f(x)=(x-2)^2-1 ?

The inverse of f(x)=(x-2)^2-1 is sqrt(x+1)+2,-sqrt(x+1)+2

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inverse of f(x)=(x-2)^2-1

inverse

f (x) = (x - 2)^{2} - 1

x + 1 + 2, - x + 1 + 2

Solution steps

y = (x - 2)^{2} - 1

Replace

x

with

y

x = (y - 2)^{2} - 1

Solve for

y, x = (y - 2)^{2} - 1

x + 1 + 2, - x + 1 + 2

f (x) = \frac{x + 3}{x - 7}

y = - 2 x + 1

f (x) = 9 + (2 + x)^{\frac{1}{2}}

y = 1 - \frac{x}{9}

f (x) = 3 - x^{3}

What is the inverse of f(x)=(x-2)^2-1 ?
The inverse of f(x)=(x-2)^2-1 is sqrt(x+1)+2,-sqrt(x+1)+2