What is the inverse of f(x)=((x-4))/(3x+5) ?

The inverse of f(x)=((x-4))/(3x+5) is (-4-5x)/(3x-1)

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inverse of f(x)=((x-4))/(3x+5)

inverse

f (x) = \frac{( x - 4 )}{3 x + 5}

\frac{- 4 - 5 x}{3 x - 1}

Solution steps

y = \frac{x - 4}{3 x + 5}

Replace

x

with

y

x = \frac{y - 4}{3 y + 5}

Solve for

y, x = \frac{y - 4}{3 y + 5}

\frac{- 4 - 5 x}{3 x - 1}

\frac{15 x ^{2}}{x + 5}

f (x) = x^{2} - 2 x + 2

f (x) = x^{2} - 4 x

f (x) = (x^{2} - 1)^{2}

f (x) = 8 x - 6 y = - 2

What is the inverse of f(x)=((x-4))/(3x+5) ?
The inverse of f(x)=((x-4))/(3x+5) is (-4-5x)/(3x-1)