What is the inverse of f(x)=2r^2+2r-1 ?

The inverse of f(x)=2r^2+2r-1 is (-1+sqrt(2r+3))/2 ,-(sqrt(2r+3)+1)/2

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inverse of f(x)=2r^2+2r-1

inverse

f (x) = 2 r^{2} + 2 r - 1

\frac{- 1 + 2 r + 3}{2}, - \frac{2 r + 3 + 1}{2}

Solution steps

x = 2 r^{2} + 2 r - 1

Replace

r

with

x

r = 2 x^{2} + 2 x - 1

Solve for

x, r = 2 x^{2} + 2 x - 1

\frac{- 1 + 2 r + 3}{2}, - \frac{2 r + 3 + 1}{2}

(- 5.1) (- 5.5)

- x^{2} - 9 x - 20

f (x) = x + 5

f (x) = 2 cos (x)

f (x) = tan (2 x)

What is the inverse of f(x)=2r^2+2r-1 ?
The inverse of f(x)=2r^2+2r-1 is (-1+sqrt(2r+3))/2 ,-(sqrt(2r+3)+1)/2