What is the symmetry y=-1/4 (x-6)(x+10) ?

The symmetry y=-1/4 (x-6)(x+10) is y=-2

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symmetry y=-1/4 (x-6)(x+10)

symmetry

y = - \frac{1}{4} (x - 6) (x + 10)

y = - 2

Solution steps

y = - \frac{1}{4} (x - 6) (x + 10)

Rewrite in standard form:

y = - \frac{x ^{2}}{4} - x + 15

y = - \frac{x ^{2}}{4} - x + 15

Axis of Symmetry for

y = a x^{2} + b x + c

x = \frac{- b}{2 a}

a = - \frac{1}{4}, b = - 1

y = \frac{- ( - 1 )}{2 ( - \frac{1}{4} )}

Refine

y = - 2

tan^{2} (x)

\frac{3 - x}{x + 2}

f (x) = \frac{( x + 1 )}{x ^{2} + 4}

f (x) = 2 x^{2} - 8 x + 3

x - y = - 5

What is the symmetry y=-1/4 (x-6)(x+10) ?
The symmetry y=-1/4 (x-6)(x+10) is y=-2