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Popular >

range of f(x)=5x^2+7

Solution

range

f (x) = 5 x^{2} + 7

Solution

f (x) \geq 7

+1

Interval Notation

[7, \infty)

Solution steps

Vertex of

5 x^{2} + 7 :

Minimum

(0, 7)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 5,

Vertex

(x_{v}, y_{v}) = (0, 7)

f (x) \geq 7

Popular Examples

f (x) = x^{2} - 2 x

monotone f(x)= 1/(x^2-6x+12)monotone intervals

f (x) = \frac{1}{x ^{2} - 6 x + 12}

domain of f(x)=x^2+5x domain

f (x) = x^{2} + 5 x

inflection (x-2)^{(4)}inflection points

(x - 2)^{(4)}

domain of f(x)=4x^3+5x^2 domain

f (x) = 4 x^{3} + 5 x^{2}

Frequently Asked Questions (FAQ)

What is the range of f(x)=5x^2+7 ?
The range of f(x)=5x^2+7 is f(x)>= 7