What is the inverse of f(x)=log_{6}(x+2)-log_{6}(2) ?

The inverse of f(x)=log_{6}(x+2)-log_{6}(2) is 3^x*2^{1+x}-2

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inverse of f(x)=log_{6}(x+2)-log_{6}(2)

inverse

f (x) = lo g_{6} (x + 2) - lo g_{6} (2)

3^{x} \cdot 2^{1 + x} - 2

Solution steps

y = lo g_{6} (x + 2) - lo g_{6} (2)

Replace

x

with

y

x = lo g_{6} (y + 2) - lo g_{6} (2)

Solve for

y, x = lo g_{6} (y + 2) - lo g_{6} (2)

3^{x} \cdot 2^{1 + x} - 2

f (x) = \frac{x ^{2} + 7 x - 18}{x ^{2} - 4}

f (x) = 4 x^{2} - 6

f (x) = \frac{x + 8}{x + 9}

f (x) = x^{3} - 7

5 x + 1

What is the inverse of f(x)=log_{6}(x+2)-log_{6}(2) ?
The inverse of f(x)=log_{6}(x+2)-log_{6}(2) is 3^x*2^{1+x}-2