What is the extreme f(x)=-6x^2+18000x ?

The extreme f(x)=-6x^2+18000x is Maximum(1500,13500000)

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extreme f(x)=-6x^2+18000x

extreme points

f (x) = - 6 x^{2} + 18000 x

Maximum (1500, 13500000)

Solution steps

f^{'} (x) = - 12 x + 18000

Find intervals:

Increasing

: - \infty < x < 1500,

Decreasing

: 1500 < x < \infty

Plug

x = 1500

into

- 6 x^{2} + 18000 x : 13500000

Maximum (1500, 13500000)

f (x) = 120 x - 0.4 x^{4} + 800

(- 2, 3), (4, 5)

f (x) = 5 x - 30

f (x) = t^{4} - 16 t^{3} + 64 t^{2}

(2, - 7), (9, - 2)

What is the extreme f(x)=-6x^2+18000x ?
The extreme f(x)=-6x^2+18000x is Maximum(1500,13500000)