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Popular >

midpoint (2,3),(12,-15)

Solution

midpoint

(2, 3), (12, - 15)

Solution

(7, - 6)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (2, 3), (x_{2}, y_{2}) = (12, - 15)

= (\frac{12 + 2}{2}, \frac{- 15 + 3}{2})

Refine

= (7, - 6)

Popular Examples

critical f(x)= 4/(x^2+8)critical points

f (x) = \frac{4}{x ^{2} + 8}

domain of f(x)= 2/(7-x)domain

f (x) = \frac{2}{7 - x}

domain of f(x)=-2^x+100 domain

f (x) = - 2^{x} + 100

domain of f(x)=(x+6)/(x^2-25)domain

f (x) = \frac{x + 6}{x ^{2} - 25}

intercepts of f(x)=(-5x+5)/(3x+7)intercepts

f (x) = \frac{- 5 x + 5}{3 x + 7}

Frequently Asked Questions (FAQ)

What is the midpoint (2,3),(12,-15) ?
The midpoint (2,3),(12,-15) is (7,-6)