What is the inverse of f(x)=-(x-4)^2+1 ?

The inverse of f(x)=-(x-4)^2+1 is sqrt(-x+1)+4,-sqrt(-x+1)+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=-(x-4)^2+1

inverse

f (x) = - (x - 4)^{2} + 1

- x + 1 + 4, - - x + 1 + 4

Solution steps

y = - (x - 4)^{2} + 1

Replace

x

with

y

x = - (y - 4)^{2} + 1

Solve for

y, x = - (y - 4)^{2} + 1

- x + 1 + 4, - - x + 1 + 4

f (x) = \frac{x ^{2}}{2} + \frac{1}{x}

g (t) = - \frac{3}{2 t ^{\frac{3}{2}}}

5 + (6 + x)^{\frac{1}{2}}

\frac{x ^{2} - 4}{x - 2}

y = 2 x

What is the inverse of f(x)=-(x-4)^2+1 ?
The inverse of f(x)=-(x-4)^2+1 is sqrt(-x+1)+4,-sqrt(-x+1)+4