What is the domain of f(x)=sqrt((4x-8)/(x+3)) ?

The domain of f(x)=sqrt((4x-8)/(x+3)) is x = 2

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domain of f(x)=sqrt((4x-8)/(x+3))

domain

f (x) = \frac{4 x - 8}{x + 3}

x < - 3 or x \geq 2

Interval Notation

(- \infty, - 3) \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x < - 3 or x \geq 2

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

x < - 3 or x \geq 2

2 + 3 + 4 x

y = \frac{2}{3} x - 5

f (x) = \frac{1}{x ^{2} + 3}

3 x^{2} + 24 x - 51

f (x) = x^{2} - 10 x + 5

What is the domain of f(x)=sqrt((4x-8)/(x+3)) ?
The domain of f(x)=sqrt((4x-8)/(x+3)) is x<-3\lor x>= 2