What is the inverse of f(x)= 1/3 x^3-6 ?

The inverse of f(x)= 1/3 x^3-6 is cube root of 3x+18

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inverse of f(x)= 1/3 x^3-6

inverse

f (x) = \frac{1}{3} x^{3} - 6

Solution steps

y = \frac{1}{3} x^{3} - 6

Replace

x

with

y

x = \frac{1}{3} y^{3} - 6

Solve for

y, x = \frac{1}{3} y^{3} - 6

- \frac{21}{( 5 + t ) ^{2}}

f (x) = \frac{- 2 x - 9}{4 x - 19}

f (x) = 2 e^{- x} - 3

8 x - 4 y = 20

f (x) = t^{\frac{1}{3}}

What is the inverse of f(x)= 1/3 x^3-6 ?
The inverse of f(x)= 1/3 x^3-6 is cube root of 3x+18