What is the inverse of f(x)=\sqrt[3]{-4x+1} ?

The inverse of f(x)=\sqrt[3]{-4x+1} is -(x^3-1)/4

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inverse of f(x)=\sqrt[3]{-4x+1}

inverse

- \frac{x ^{3} - 1}{4}

Solution steps

Replace

x

with

y

Solve for

- \frac{x ^{3} - 1}{4}

f (x) = \frac{2 x ^{2} - x - 7}{x ^{2} + 4}

f (x) = 1 - (x - 4)^{2}

\frac{4}{x} + 6

f (x) = \frac{5}{x ^{2} - 4}

f (x) = 8 x + 6

What is the inverse of f(x)=\sqrt[3]{-4x+1} ?
The inverse of f(x)=\sqrt[3]{-4x+1} is -(x^3-1)/4