What is the inverse of f(x)=x^2+4x-1 ?

The inverse of f(x)=x^2+4x-1 is -2+sqrt(x+5),-sqrt(x+5)-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=x^2+4x-1

inverse

f (x) = x^{2} + 4 x - 1

- 2 + x + 5, - x + 5 - 2

Solution steps

y = x^{2} + 4 x - 1

Replace

x

with

y

x = y^{2} + 4 y - 1

Solve for

y, x = y^{2} + 4 y - 1

- 2 + x + 5, - x + 5 - 2

(1, 9), (7, - 7)

(4, 2), (- 6, - 6)

f (x) = - 5 x - 6

x^{3} + 3 x^{2} + 2 x + 1

f (x) = \frac{x ^{2} + x - 2}{x ^{2} - 3 x - 4}

What is the inverse of f(x)=x^2+4x-1 ?
The inverse of f(x)=x^2+4x-1 is -2+sqrt(x+5),-sqrt(x+5)-2