What is the inverse of f(x)=(100)/(x^2) ?

The inverse of f(x)=(100)/(x^2) is (10sqrt(x))/x ,-(10sqrt(x))/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(100)/(x^2)

inverse

f (x) = \frac{100}{x ^{2}}

\frac{10 x}{x}, - \frac{10 x}{x}

Solution steps

y = \frac{100}{x ^{2}}

Replace

x

with

y

x = \frac{100}{y ^{2}}

Solve for

y, x = \frac{100}{y ^{2}}

\frac{10 x}{x}, - \frac{10 x}{x}

f (x) = (\frac{x}{3} + \frac{6}{3})^{\frac{1}{3}}

f (x) = \frac{1}{9 x ^{3}}

f (x) = \frac{5}{2}

y = 5 x^{2}

f (x) = x^{\frac{6}{7}} - x^{\frac{13}{7}}

What is the inverse of f(x)=(100)/(x^2) ?
The inverse of f(x)=(100)/(x^2) is (10sqrt(x))/x ,-(10sqrt(x))/x