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Popular >

range of f(x)=-x^2+1

Solution

range

f (x) = - x^{2} + 1

Solution

f (x) \leq 1

+1

Interval Notation

(- \infty, 1]

Solution steps

Vertex of

- x^{2} + 1 :

Maximum

(0, 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (0, 1)

f (x) \leq 1

Popular Examples

inverse of f(x)=(x-1)/5 inverse

f (x) = \frac{x - 1}{5}

domain of (x/(x+3))/(x/(x+3)+3)domain

\frac{\frac{x}{x + 3}}{\frac{x}{x + 3} + 3}

midpoint (-11,5),(34,-23)midpoint

(- 11, 5), (34, - 23)

line m= 2/3 ,(-2,6)line

m = \frac{2}{3}, (- 2, 6)

inverse of f(x)= 9/5 c+32 inverse

f (x) = \frac{9}{5} c + 32

Frequently Asked Questions (FAQ)

What is the range of f(x)=-x^2+1 ?
The range of f(x)=-x^2+1 is f(x)<= 1