What is the asymptotes of y=(2e^x)/(e^x-5) ?

The asymptotes of y=(2e^x)/(e^x-5) is Vertical: x=ln(5),Horizontal: y=2,y=0

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asymptotes of y=(2e^x)/(e^x-5)

asymptotes

y = \frac{2 e ^{x}}{e ^{x} - 5}

Vertical : x = ln (5), Horizontal : y = 2, y = 0

Solution steps

Vertical asymptotes of

\frac{2 e ^{x}}{e ^{x} - 5} : x = ln (5)

Horizontal Asymptotes of

\frac{2 e ^{x}}{e ^{x} - 5} : y = 2, y = 0

Slant Asymptotes of

\frac{2 e ^{x}}{e ^{x} - 5} :

None

Vertical : x = ln (5), Horizontal : y = 2, y = 0

f (x) = \frac{x ^{2} + 2}{x + 4}

f (x) = 8 - 4 x

f (x) = 3 x^{3}

f (x) = \frac{4 x}{x ^{2} + 1} + 98.6

f (x) = x^{2} (x - 5) (x - 3)

What is the asymptotes of y=(2e^x)/(e^x-5) ?
The asymptotes of y=(2e^x)/(e^x-5) is Vertical: x=ln(5),Horizontal: y=2,y=0