What is the domain of y=(sqrt(10+x))/(1-x) ?

The domain of y=(sqrt(10+x))/(1-x) is -10 1

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domain of y=(sqrt(10+x))/(1-x)

domain

y = \frac{10 + x}{1 - x}

- 10 \leq x < 1 or x > 1

Solution steps

Find non-negative values for radicals:

x \geq - 10

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

- 10 \leq x < 1 or x > 1

\frac{7}{x ^{2}}

f (x) = x^{2} - 6 x + 9

g (x) = x^{2} + 6 x + 7

x^{2} - 5

2 sin (4 x - π)

What is the domain of y=(sqrt(10+x))/(1-x) ?
The domain of y=(sqrt(10+x))/(1-x) is -10<= x<1\lor x>1