What is the inverse of f(x)=(2x-1)^2 ?

The inverse of f(x)=(2x-1)^2 is (sqrt(x)+1)/2 ,(-sqrt(x)+1)/2

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inverse of f(x)=(2x-1)^2

inverse

f (x) = (2 x - 1)^{2}

\frac{x + 1}{2}, \frac{- x + 1}{2}

Solution steps

y = (2 x - 1)^{2}

Replace

x

with

y

x = (2 y - 1)^{2}

Solve for

y, x = (2 y - 1)^{2}

\frac{x + 1}{2}, \frac{- x + 1}{2}

(6, 25.4), (19, 24.1)

f (x) = - x + 6

(3, - 2), (8, - 5)

y = e^{5 x}

- \frac{3}{x}

What is the inverse of f(x)=(2x-1)^2 ?
The inverse of f(x)=(2x-1)^2 is (sqrt(x)+1)/2 ,(-sqrt(x)+1)/2