What is the domain of x/(sqrt(9-x^2)) ?

The domain of x/(sqrt(9-x^2)) is -3<x<3

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domain of x/(sqrt(9-x^2))

domain

\frac{x}{9 - x ^{2}}

- 3 < x < 3

Interval Notation

(- 3, 3)

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 3 < x < 3

y = 4 x + 2

(x + 5)^{2} - 4

y = \frac{4}{3} x - 2

2 x - 3 y = 8

\frac{- 1}{x} - 1