What is the asymptotes of f(x)= 1/(x^2-9) ?

The asymptotes of f(x)= 1/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0

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asymptotes of f(x)= 1/(x^2-9)

asymptotes

f (x) = \frac{1}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{1}{x ^{2} - 9} : y = 0

Slant Asymptotes of

\frac{1}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 0

f (x) = 2 x^{2} - \frac{1}{x}

\frac{8 - x ^{3}}{2 x ^{2}}

f (x) = 3 - 4 x^{2}

2 x - 5 ln (4 x + 2)

f (x) = \frac{2 x - 5}{x - 3}

What is the asymptotes of f(x)= 1/(x^2-9) ?
The asymptotes of f(x)= 1/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0