What is the slope ofintercept x+3y-3=0 ?

The slope ofintercept x+3y-3=0 is y=-1/3 x+1

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slope ofintercept x+3y-3=0

slope intercept

x + 3 y - 3 = 0

y = - \frac{1}{3} x + 1

Solution steps

x + 3 y - 3 = 0

Convert to slope intercept form:

y = - \frac{1}{3} x + 1

For a line in the form of

y = mx + b

, the slope is

m

and

y

intercept is

b

y = - \frac{1}{3} x + 1

0

f (x) = 64 - x^{2}

f (x) = \frac{3 x}{( 1 - 5 x )}

\frac{x - 2}{x + 2}

f (x) = 3 x^{4} - 4 x^{3} - 12 x^{2}

What is the slope ofintercept x+3y-3=0 ?
The slope ofintercept x+3y-3=0 is y=-1/3 x+1