What is the inverse of f(x)= x/(sqrt(x^2+7)) ?

The inverse of f(x)= x/(sqrt(x^2+7)) is sqrt(-(7x^2)/(x^2-1)),-sqrt(-(7x^2)/(x^2-1))

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inverse of f(x)= x/(sqrt(x^2+7))

inverse

f (x) = \frac{x}{x ^{2} + 7}

- \frac{7 x ^{2}}{x ^{2} - 1}, - - \frac{7 x ^{2}}{x ^{2} - 1}

Solution steps

y = \frac{x}{x ^{2} + 7}

Replace

x

with

y

x = \frac{y}{y ^{2} + 7}

Solve for

y, x = \frac{y}{y ^{2} + 7}

- \frac{7 x ^{2}}{x ^{2} - 1}, - - \frac{7 x ^{2}}{x ^{2} - 1}

(7, 4), (- 1, - 4)

2 t

f (x) = 4 x^{2} - 8 x + 2

f (x) = \frac{x + 5}{( x ^{2} - 10 x + 25 )}

What is the inverse of f(x)= x/(sqrt(x^2+7)) ?
The inverse of f(x)= x/(sqrt(x^2+7)) is sqrt(-(7x^2)/(x^2-1)),-sqrt(-(7x^2)/(x^2-1))