What is the range of f(X)=log_{3}(1/9) ?

The range of f(X)=log_{3}(1/9) is f(X)=-2

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range of f(X)=log_{3}(1/9)

range

f (X) = lo g_{3} (\frac{1}{9})

f (X) = - 2

Interval Notation

f (X) = - 2

Solution steps

Simplify

lo g_{3} (\frac{1}{9}) : - 2

The range of constant function

f (x) = a

is constant

a

f (X) = - 2

\frac{x ^{2} - 5 x + 4}{x + 1}

- x^{3} + 3 x^{2} + 10 x

f (x) = - 2 x + 4 - 1

0 = 6.3 + 0 (1.188 - 0) \frac{1}{2} x (1.188 - 0)^{2}

What is the range of f(X)=log_{3}(1/9) ?
The range of f(X)=log_{3}(1/9) is f(X)=-2