What is the domain of y= 5/(x^2-1) ?

The domain of y= 5/(x^2-1) is x 1

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domain of y= 5/(x^2-1)

domain

y = \frac{5}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = x^{2} + 2

\frac{4 x + 8}{3 x - 2}

f (x) = - 4 x + 8

3^{\frac{1}{x}}

f (x) = tan (x + (\frac{7 π}{6}))

What is the domain of y= 5/(x^2-1) ?
The domain of y= 5/(x^2-1) is x<-1\lor-1<x<1\lor x>1