What is the inverse of f(x)=(x-13)^2 ?

The inverse of f(x)=(x-13)^2 is sqrt(x)+13,-sqrt(x)+13

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inverse of f(x)=(x-13)^2

inverse

f (x) = (x - 13)^{2}

x + 13, - x + 13

Solution steps

y = (x - 13)^{2}

Replace

x

with

y

x = (y - 13)^{2}

Solve for

y, x = (y - 13)^{2}

x + 13, - x + 13

f (x) = (x^{3} + 2)^{3} + 2

y = 7^{x}

x^{4} - 4 x^{3} - x^{2} + 14 x + 10

- \frac{19}{( 6 + t ) ^{2}}

\frac{1}{x ^{3} - 5 x ^{2} + 3 x - 1}

What is the inverse of f(x)=(x-13)^2 ?
The inverse of f(x)=(x-13)^2 is sqrt(x)+13,-sqrt(x)+13