What is the domain of f(x)= 1/(sqrt(x-1)) ?

The domain of f(x)= 1/(sqrt(x-1)) is x>1

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domain of f(x)= 1/(sqrt(x-1))

domain

f (x) = \frac{1}{x - 1}

x > 1

Interval Notation

(1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x > 1

\frac{6 x - 1}{2 x + 5}

f (x) = \frac{9}{x}

g (x) = \frac{x ^{2}}{x - 4}

f (x) = \frac{1}{2} x + 6

f (x) = \frac{3 x ^{2}}{x ^{2} - 16}

What is the domain of f(x)= 1/(sqrt(x-1)) ?
The domain of f(x)= 1/(sqrt(x-1)) is x>1