What is the inverse of f(x)=4^{x+1}-3 ?

The inverse of f(x)=4^{x+1}-3 is (ln(x+3))/(2ln(2))-1

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inverse of f(x)=4^{x+1}-3

inverse

f (x) = 4^{x + 1} - 3

\frac{ln ( x + 3 )}{2 ln ( 2 )} - 1

Solution steps

y = 4^{x + 1} - 3

Replace

x

with

y

x = 4^{y + 1} - 3

Solve for

y, x = 4^{y + 1} - 3

\frac{ln ( x + 3 )}{2 ln ( 2 )} - 1

f (x) = 3 x^{2} + 5 x - 2

x^{4} - 4 x^{3}

y = \frac{2}{x + 3} - 1

f (x) = - \frac{x ^{3}}{3} + 16 x

f (x) = 4 - 2 2 - 4 x

What is the inverse of f(x)=4^{x+1}-3 ?
The inverse of f(x)=4^{x+1}-3 is (ln(x+3))/(2ln(2))-1