What is the inverse of f(x)=((x-1))/(x+2) ?

The inverse of f(x)=((x-1))/(x+2) is (-1-2x)/(x-1)

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inverse of f(x)=((x-1))/(x+2)

inverse

f (x) = \frac{( x - 1 )}{x + 2}

\frac{- 1 - 2 x}{x - 1}

Solution steps

y = \frac{x - 1}{x + 2}

Replace

x

with

y

x = \frac{y - 1}{y + 2}

Solve for

y, x = \frac{y - 1}{y + 2}

\frac{- 1 - 2 x}{x - 1}

\frac{5}{x}

f (x) = 3 cos (2 x) + 2

y = - x + 1, (2, 6)

f (x) = y^{2} - 4

7 x - 14 y = - 56

What is the inverse of f(x)=((x-1))/(x+2) ?
The inverse of f(x)=((x-1))/(x+2) is (-1-2x)/(x-1)