What is the extreme f(x)=x^3-48x+7 ?

The extreme f(x)=x^3-48x+7 is Maximum(-4,135),Minimum(4,-121)

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extreme f(x)=x^3-48x+7

extreme points

f (x) = x^{3} - 48 x + 7

Maximum (- 4, 135), Minimum (4, - 121)

Solution steps

f^{'} (x) = 3 x^{2} - 48

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 4

into

x^{3} - 48 x + 7 : 135

Maximum (- 4, 135)

Plug

x = 4

into

x^{3} - 48 x + 7 : - 121

Minimum (4, - 121)

Maximum (- 4, 135), Minimum (4, - 121)

(2.5, 9.2), (- 0.5, 6.2)

f (x) = \frac{x}{2} - 5

f (x) = \frac{4}{x + 9}

f (x) = \frac{3 x ^{3} + 3}{x ^{2} - 3 x - 4}

(- 2, - 4), (3, - 7)

What is the extreme f(x)=x^3-48x+7 ?
The extreme f(x)=x^3-48x+7 is Maximum(-4,135),Minimum(4,-121)