What is the critical 8-3x-2x^2 ?

The critical 8-3x-2x^2 is x=-3/4

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critical 8-3x-2x^2

critical points

8 - 3 x - 2 x^{2}

x = - \frac{3}{4}

Solution steps

8 - 3 x - 2 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{3}{4}

Identify critical points not in

f (x)

domain

Domain of

8 - 3 x - 2 x^{2} : - \infty < x < \infty

All critical points are in domain

x = - \frac{3}{4}

f (x) = e^{- 4 t}

y = x^{2} + 4

y = (x + 3)^{2}

(14, - 1.5), (16, 0)

f (x) = \frac{x - 8}{x - 2}