What is the intercepts of f(x)=2y(y-3)(y+1)^2 ?

The intercepts of f(x)=2y(y-3)(y+1)^2 is X Intercepts: (0,0),(3,0),(-1,0),Y Intercepts: (0,0)

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intercepts of f(x)=2y(y-3)(y+1)^2

intercepts

f (x) = 2 y (y - 3) (y + 1)^{2}

X Intercepts : (0, 0), (3, 0), (- 1, 0), Y Intercepts : (0, 0)

Solution steps

x -

axis interception points of

2 y (y - 3) (y + 1)^{2} : (0, 0), (3, 0), (- 1, 0)

y -

axis interception point of

2 y (y - 3) (y + 1)^{2} : (0, 0)

X Intercepts : (0, 0), (3, 0), (- 1, 0), Y Intercepts : (0, 0)

f (x) = \frac{1}{x ^{2} + 1}

\frac{2}{3} x + 4 - 1

f (x) = x^{2} + x - 2

f (x) = x^{3} - x^{2} + 4 x + 2

\frac{x + 2}{6}

What is the intercepts of f(x)=2y(y-3)(y+1)^2 ?
The intercepts of f(x)=2y(y-3)(y+1)^2 is X Intercepts: (0,0),(3,0),(-1,0),Y Intercepts: (0,0)