What is the domain of f(x)=((2x+1))/(x^2+x-2) ?

The domain of f(x)=((2x+1))/(x^2+x-2) is x 1

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domain of f(x)=((2x+1))/(x^2+x-2)

domain

f (x) = \frac{( 2 x + 1 )}{x ^{2} + x - 2}

x < - 2 or - 2 < x < 1 or x > 1

Interval Notation

(- \infty, - 2) \cup (- 2, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 2

The function domain

x < - 2 or - 2 < x < 1 or x > 1

f (x) = \frac{x ^{3}}{3} - 4 x

f (x) = \frac{x}{6 x ^{2} + 5 x - 1}

f (x) = \frac{3 x}{x + 5}

y = 5 x - 9

f (x) = x^{2} + 5 x + 6

What is the domain of f(x)=((2x+1))/(x^2+x-2) ?
The domain of f(x)=((2x+1))/(x^2+x-2) is x<-2\lor-2<x<1\lor x>1