What is the inverse of f(x)=(x^2-3)/5 ?

The inverse of f(x)=(x^2-3)/5 is sqrt(5x+3),-sqrt(5x+3)

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inverse of f(x)=(x^2-3)/5

inverse

f (x) = \frac{x ^{2} - 3}{5}

5 x + 3, - 5 x + 3

Solution steps

y = \frac{x ^{2} - 3}{5}

Replace

x

with

y

x = \frac{y ^{2} - 3}{5}

Solve for

y, x = \frac{y ^{2} - 3}{5}

5 x + 3, - 5 x + 3

x^{2} + 12 x + 11

f (x) = x^{3} + 4 x

y = - 2 x^{2} + 8

f (x) = x e^{- 6 x}

y = (\frac{1}{2})^{x} + 1

What is the inverse of f(x)=(x^2-3)/5 ?
The inverse of f(x)=(x^2-3)/5 is sqrt(5x+3),-sqrt(5x+3)