What is the critical x^3-6x^2+9x+1 ?

The critical x^3-6x^2+9x+1 is x=1,x=3

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critical x^3-6x^2+9x+1

critical points

x^{3} - 6 x^{2} + 9 x + 1

x = 1, x = 3

Solution steps

x^{3} - 6 x^{2} + 9 x + 1

Find where

f^{'} (x)

is equal to zero or undefined

x = 1, x = 3

Identify critical points not in

f (x)

domain

Domain of

x^{3} - 6 x^{2} + 9 x + 1 : - \infty < x < \infty

All critical points are in domain

x = 1, x = 3

f (x) = 25 x - x^{2}

y = - \frac{1}{2} x - 1, (3, 2)

f (x) = \frac{1}{3} x - 5

3 x^{3}