What is the shift f(x)=cos(2x+pi) ?

The shift f(x)=cos(2x+pi) is Phase:-pi/2 , Vertical:0

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shift f(x)=cos(2x+pi)

shift

f (x) = cos (2 x + π)

Phase : - \frac{π}{2}, Vertical : 0

Solution steps

f (x) = cos (2 x + π)

g (B x - C) = cos (2 x + π), B = 2, C = - π, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- π}{2}

- \frac{π}{2}

The vertical shift

D

0

0

f (x) = 4 x^{2} + 2 x - 1

f (x) = \frac{1}{4} x^{2}

(3.4) (0)

f (x) = x^{3} - 3 x - 2

g (t) = \frac{13}{1 + 3 ^{- t}}

What is the shift f(x)=cos(2x+pi) ?
The shift f(x)=cos(2x+pi) is Phase:-pi/2 , Vertical:0