What is the inverse of f(x)=x^2-4x+5 ?

The inverse of f(x)=x^2-4x+5 is 2+sqrt(x-1),2-sqrt(x-1)

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inverse of f(x)=x^2-4x+5

inverse

f (x) = x^{2} - 4 x + 5

2 + x - 1, 2 - x - 1

Solution steps

y = x^{2} - 4 x + 5

Replace

x

with

y

x = y^{2} - 4 y + 5

Solve for

y, x = y^{2} - 4 y + 5

2 + x - 1, 2 - x - 1

(0, - 2), (4, 2)

f (x) = - x^{2} + 2 x - 4

ln (x^{2} - 9)

f (x) = (\frac{1}{x ^{5} + x + 1})

\frac{1}{cos ^{2} ( x )}

What is the inverse of f(x)=x^2-4x+5 ?
The inverse of f(x)=x^2-4x+5 is 2+sqrt(x-1),2-sqrt(x-1)