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Popular >

midpoint (-1,1),(-10,-5)

Solution

midpoint

(- 1, 1), (- 10, - 5)

Solution

(- \frac{11}{2}, - 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 1, 1), (x_{2}, y_{2}) = (- 10, - 5)

= (\frac{- 10 - 1}{2}, \frac{- 5 + 1}{2})

Refine

= (- \frac{11}{2}, - 2)

Popular Examples

domain of f(x)=(x^3)/3 domain

f (x) = \frac{x ^{3}}{3}

periodicity of f(x)=sin(x/6)periodicity

f (x) = sin (\frac{x}{6})

range of (12-x-x^2)/(|x-3|)range

\frac{12 - x - x ^{2}}{∣ x - 3 ∣}

inverse of f(x)=2(x-1)^2+7 inverse

f (x) = 2 (x - 1)^{2} + 7

critical f(x)=2(3-x)critical points

f (x) = 2 (3 - x)

Frequently Asked Questions (FAQ)

What is the midpoint (-1,1),(-10,-5) ?
The midpoint (-1,1),(-10,-5) is (-11/2 ,-2)