What is the inverse of f(x)=2(x-1)^2+7 ?

The inverse of f(x)=2(x-1)^2+7 is sqrt((x-7)/2)+1,-sqrt((x-7)/2)+1

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inverse of f(x)=2(x-1)^2+7

inverse

f (x) = 2 (x - 1)^{2} + 7

\frac{x - 7}{2} + 1, - \frac{x - 7}{2} + 1

Solution steps

y = 2 (x - 1)^{2} + 7

Replace

x

with

y

x = 2 (y - 1)^{2} + 7

Solve for

y, x = 2 (y - 1)^{2} + 7

\frac{x - 7}{2} + 1, - \frac{x - 7}{2} + 1

f (x) = 2 (3 - x)

(0, 2), (- 3, \frac{3}{2})

f (x) = \frac{x ^{2} - x - 6}{x ^{2} - 6 x + 8}

f (x) = \frac{e ^{x}}{x - 1}

f (x) = \frac{2 x ^{2} - x - 8}{x ^{2} + 9}

What is the inverse of f(x)=2(x-1)^2+7 ?
The inverse of f(x)=2(x-1)^2+7 is sqrt((x-7)/2)+1,-sqrt((x-7)/2)+1