What is the asymptotes of f(x)=((x^2+1))/(3x-2x^2) ?

The asymptotes of f(x)=((x^2+1))/(3x-2x^2) is Vertical: x=0,x= 3/2 ,Horizontal: y=-1/2

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asymptotes of f(x)=((x^2+1))/(3x-2x^2)

asymptotes

f (x) = \frac{( x ^{2} + 1 )}{3 x - 2 x ^{2}}

Vertical : x = 0, x = \frac{3}{2}, Horizontal : y = - \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{3 x - 2 x ^{2}} : x = 0, x = \frac{3}{2}

Horizontal Asymptotes of

\frac{x ^{2} + 1}{3 x - 2 x ^{2}} : y = - \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} + 1}{3 x - 2 x ^{2}} :

None

Vertical : x = 0, x = \frac{3}{2}, Horizontal : y = - \frac{1}{2}

f (x) = \frac{- 3}{x + 4}

f (x) = \frac{x ^{2}}{x - 2}

f (x) = - \frac{3}{2} + 1

f (x) = \frac{x ^{3}}{x ^{4}}

f (x) = \frac{4 x + 5}{2 - 5 x}

What is the asymptotes of f(x)=((x^2+1))/(3x-2x^2) ?
The asymptotes of f(x)=((x^2+1))/(3x-2x^2) is Vertical: x=0,x= 3/2 ,Horizontal: y=-1/2