What is the domain of f(x)= 1/(x^2-x-90) ?

The domain of f(x)= 1/(x^2-x-90) is x 10

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domain of f(x)= 1/(x^2-x-90)

domain

f (x) = \frac{1}{x ^{2} - x - 90}

x < - 9 or - 9 < x < 10 or x > 10

Interval Notation

(- \infty, - 9) \cup (- 9, 10) \cup (10, \infty)

Solution steps

Find undefined (singularity) points:

x = 10, x = - 9

The function domain

x < - 9 or - 9 < x < 10 or x > 10

f (x) = \frac{( x - 1 )}{( x + 2 )}

f (x) = \frac{x + 7}{x ^{2} - x - 56}

0.5 \cdot 80 + 25

f (x) = 65

f (x) = \frac{1}{2} \cdot 2^{x}

What is the domain of f(x)= 1/(x^2-x-90) ?
The domain of f(x)= 1/(x^2-x-90) is x<-9\lor-9<x<10\lor x>10