What is the inverse of f(x)=((x-1))/((x+2)) ?

The inverse of f(x)=((x-1))/((x+2)) is (-1-2x)/(x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=((x-1))/((x+2))

inverse

f (x) = \frac{( x - 1 )}{( x + 2 )}

\frac{- 1 - 2 x}{x - 1}

Solution steps

y = \frac{x - 1}{x + 2}

Replace

x

with

y

x = \frac{y - 1}{y + 2}

Solve for

y, x = \frac{y - 1}{y + 2}

\frac{- 1 - 2 x}{x - 1}

f (x) = \frac{x + 7}{x ^{2} - x - 56}

0.5 \cdot 80 + 25

f (x) = 65

f (x) = \frac{1}{2} \cdot 2^{x}

f (x) = \frac{x ^{2} + 2 x + 1}{3 x ^{2} - x - 4}

What is the inverse of f(x)=((x-1))/((x+2)) ?
The inverse of f(x)=((x-1))/((x+2)) is (-1-2x)/(x-1)